(3x-1)^2+2x(1-x)+2=x-7(1-x)x

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Solution for (3x-1)^2+2x(1-x)+2=x-7(1-x)x equation:



(3x-1)^2+2x(1-x)+2=x-7(1-x)x
We move all terms to the left:
(3x-1)^2+2x(1-x)+2-(x-7(1-x)x)=0
We add all the numbers together, and all the variables
(3x-1)^2+2x(-1x+1)-(x-7(-1x+1)x)+2=0
We multiply parentheses
-2x^2+(3x-1)^2+2x-(x-7(-1x+1)x)+2=0
We calculate terms in parentheses: -(x-7(-1x+1)x), so:
x-7(-1x+1)x
We multiply parentheses
7x^2+x-7x
We add all the numbers together, and all the variables
7x^2-6x
Back to the equation:
-(7x^2-6x)
We add all the numbers together, and all the variables
-2x^2+2x+(3x-1)^2-(7x^2-6x)+2=0
We get rid of parentheses
-2x^2-7x^2+2x+(3x-1)^2+6x+2=0
We add all the numbers together, and all the variables
-9x^2+8x+(3x-1)^2+2=0
We move all terms containing x to the left, all other terms to the right
-9x^2+8x+(3x-1)^2=-2

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